x^2+9x=112

Solution for x^2+9x=112 equation:

x^2+9x=112

We move all terms to the left:

x^2+9x-(112)=0

a = 1; b = 9; c = -112;
Δ = b2-4ac
Δ = 92-4·1·(-112)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-23}{2*1}=\frac{-32}{2}
=-16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+23}{2*1}=\frac{14}{2}
=7
$